Berlin interview questions | Glassdoor.co.in

# Interview questions in Berlin

Zalando Interviews in Berlin

jobs.zalando.com /  HQ: Berlin

317 Interviews in Berlin (of 560)

2.8 Average

GetYourGuide Interviews in Berlin

www.getyourguide.com /  HQ: Berlin

164 Interviews in Berlin (of 263)

3.1 Average

N26 Interviews in Berlin

www.n26.com /  HQ: Berlin

124 Interviews in Berlin (of 251)

2.8 Average

## Interview Questions in Berlin

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23 Dec 2015

26 Feb 2018

### Junior Marketing Analyst at Zalando was asked...

14 Nov 2016
 (talk about yourself, start date, do you have any questions)4 AnswersHey there! Could you please tell me more about the online test? (like what kind of questions were involved). I have to do the test soon myself. I will be indebted to you :)It was an Aptitude test, try to practice before taking the test. And some behavioral questions.So it was just basic math and logic? Thank you so much for taking the time out to answer :)Show more responsesCoz I went to the company's website (that does the test), hoping that they might have a mock test that I could perhaps take, but they didn't seem to have any. You are my only source of info at the moment (did a lot of searching on google, no luck).

2 May 2015

### Senior Software Engineer at Zalando was asked...

19 Jan 2018
 How to convert an Optional string to integer without throwing exception4 Answersuse filter and mapWell its pretty basic. 1. Convert String into character array. 2. Check if Array's length = 48 && intValue <= 57) { int numValue = values[intValue - 48]; finalNumber += (numValue * Math.pow(10, power)); power--; } else { System.out.println("Not a number"); return; } } finalNumber *= multiplier; System.out.println(finalNumber); }Program ___________________________________________ int[] values = {0,1,2,3,4,5,6,7,8,9}; String test = "-123"; char[] arr = test.toCharArray(); if(arr.length = 48 && intValue <= 57) { int numValue = values[intValue - 48]; finalNumber += (numValue * Math.pow(10, power)); power--; } else { System.out.println("Not a number"); return; } } finalNumber *= multiplier; System.out.println(finalNumber); }Show more responsesglassdoor not allowing to post full code.

21 Nov 2015

27 Apr 2015

### Senior Data Engineer at Zalando was asked...

9 Sep 2016
 If you take 3 subsequent number (n, n+1, n+2) and know, that n and n+2 are prime numbers, can you proove, that n+1 is always dividable by 6?3 Answers1. if n and n+2 are prime, the n+1 is dividable by 2; 2.one of the three subsequent number (n, n+1, n+2) must be dividable by 3. because n and n+2 are prime, then n+1 is dividable by 3. So n+1 is dividable by 6.3, 4, 5. 3 and 5 are prime. 4 is not divisible by 6.n+1 will be divisible by 2 since n and n+2 are prime now n,n+1 or n+2 any one of them should be divisible by 3 n and n+2 are prime so n+1 should be divisible by 3 Hence proved

### Front-End Developer at Zalando was asked...

2 Oct 2015
 Convert all the words with 3 alphabets to upper case in a sentence.(JS)3 Answersfunction convert(string){ return string.split(' ').map(function(value){ if(value.length == 3) return value.toUpperCase(); return value; }).join(' '); }better way is: function convertStr(str, limit){ if(limit === 0){return new Error("required limit is minimum 1")}; var temp = str.split(''); for(var i=0; isentences = "ben seni severim cocuk" sentences.split(" ").map(word => convert(word)) function convert(word){ if(word.length === 3) { word = word.toUpperCase(); return word } return word }

### Associate at KWS Group was asked...

28 Mar 2019
 How are you?3 AnswersDid we book another date for interview?! Ok, bye!more detailmore detail
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