Analyst Interview Questions in Boston, MA | Glassdoor.co.in

# Analyst Interview Questions in Boston, MA, US

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## Top Interview Questions

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21 Nov 2014

### Q & A Analyst Training Program at Eze Software was asked...

26 Apr 2010
 Scenario: You have 8 golf balls and 1 is heavier than the 7 others. All you have is a balance used in chemistry classes. What is the shortest number of times you could measure the golf balls to find the heaviest ball?6 AnswersYou have to keep in mind that you're dividing up the balls. They try to confuse you, but just ignore the people and stick to your intuition. The quickest way to discover the heaviest ball was in 2 steps.i would say three. you could put 4 balls on each side and then take the heavier side. split that group into two balls on each side. then lastly split that group to have one ball on each side.i would say three. you could put 4 balls on each side and then take the heavier side. split that group into two balls on each side. then lastly split that group to have one ball on each side.Show more responses2 steps. 1. Put 3 balls on each side of the scale measure( [123], [456] ) If each group of 3 is equal: 2. Place the remaining two balls on the scale - measure( [7], [8] ) If each group of 3 is not equal: assuming [123] is heavier than [456] 2. Take 2 balls from the heavier group from step 1 and place them on the scale. measure( [1], [2] ) If they are equal then [3] is the heaviest3 v. 3 Case 1: Heavier ball lies within the first 3v3 weighing. Weigh 2 of the balls on the heavier side. Either one is heavier or they balance. If they balance, then it's the 3rd one we didn't weigh. Done. Case 2: 3v3 balances. Then the heavier ball lies within the other 3 not weighed. Weigh 1v1, either it balances or it doesn't. If it doesn't, we're done because we can see that one side is heavier. If it does, then it's the third one not being weighed. Minimum amount of weighings is 2.in 2 steps. Put total 6 balls 3 each side on scale, Heavier side has one heavy ball. if not then the (remaining (2) has it) Heavier side . from 3 put (2) one scale if any was heavier you got it, if they were equal (1) remaining is heavier one. if(both sides balls were equal)....then go for the remaining (2) and scale them.

12 Aug 2011

### Records Examiner/Analyst at FSA was asked...

7 May 2015
 If I was comfortable working in a law enforcement environment.4 AnswersYes, I had previously worked with cops and was familiar with the culture of law enforcement.How long did the whole process including the background check take?About 3 months.Show more responsesWhat did they ask for virtual prescreening?

### Q & A Analyst Training Program at Eze Software was asked...

26 Apr 2010
 Scenario: If you were running late for a job interview and you had no lights on in your apartment. Let's say you went into your dresser drawer and had to pull out one pair of socks. All you had was black or brown socks. And there were 5 socks total, what is the least amount of pulls you could do?4 Answersbasically you have to keep in mind the probability of pulling out each sock. the shortest answer would be 2 pulls.You have to pull out three socks to be sure that you had at least two of one color.it would have to be three socks because if you pulled just two, you could get one black and one brown.Show more responsesit's 2. You could be lucky and get 2 socks of the same color.

### Financial Analyst at PSG Global Solutions was asked...

28 Feb 2019

25 Apr 2015
 Phone Interview #2 You are playing a game of baseball. There are two outs in the bottom of the ninth, and you are down by one run. You are currently a baserunner on first base. [Obviously, you must score or else the game ends]. A)You are trying to figure out if you should steal second base or not. What kind of information do you need to know to inform this decision? B) Every batter in your lineup has identical odds.They get a single 50% of the time and they strike out 50% of the time. If you are on first base, you cannot score on a single. If you are on second, you are guaranteed to score on a single. You successfully steal 75% of the time. Should you steal? [I may be missing some of the nonsense here, but this is all the relevant information] C) It turns out the pitcher acts a bit differently with a runner on second [regardless of who the batter is] and no other runners on base. Under these circumstances, he is 50% to strike them out, 40% to surrender a walk, and 10% to surrender a hit. How does this change things/ should you steal?3 AnswersA) Ultimately, you need to know the odds of you scoring without stealing, the odds of you scoring if you successfully steal, and the odds of successfully stealing. There are other factors, but this is what it all ultimately boils down to. B) Odds of you scoring when attempting to steal are .75*.5 = .325. Odds of you scoring waiting for two successful base hits [whats required] are .5*.5 =.25. You should steal. C) You're still .25 to score hoping for two hits in a row. Stealing now changes the equation to .75(.1+.4(.5)) because you need steal+hit or steal+walk+hit = .75(.3) = .225. You should not steal.(C) is not as straightforward as the previous answer suggests. After a hit, are you on 3rd or 2nd? How does that change the probability for the pitcher/hitter? All things considered, you should still steal. You have the following scenarios in which you score: Steal&Hit or Steal&Walk&Hit or Steal&Walk&Walk&Hit or Steal&Walk&Walk&Walk. In all of these scenarios, a runner reaches 2nd, so our new probabilities are used. The final prob should be %16.5. If you don't steal, you have these scenarios: Hit(.50 prob) &Hit(.10 prob assuming 2nd & 3rd baserunners have same impact) or Hit&Walk&Hit or Hit&Walk&Walk&Hit or Hit&Walk&Walk&Walk. This yields prob of %11, given that baserunners in scoring position are the cause of the new probability, not just on second. Again, these would be things to clarify in the interviewTo the more recent post: No the original answer is correct. If there's a hit the runner from 2nd scores, a runner on 1st goes to 2nd. There's no such thing as a Steal-Walk-Walk because this pitcher's oddity only applies when there's a runner on 2nd and nobody else on base.

29 Jun 2014