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Member of Technical Staff Interview Questions


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given 8 coins and one of them heavier than the others, how many weighings will be needed to find the odd one ?

4 Answers

two weighings are needed. separate into three groups (3,3,2) put three on each side of scale, if sides balance then place two remaining coins on either side of scale to see which is heavier. If sides don't balance, take two coins from the heavier side and put on the scale to see if one is heavier, if they balance, the one you took off is the heaviest.

One weighing. Place four coins in each pan. Take two off at a time until the scale balances. The heavier coin will be in the hand of the pan that ascends.

@Cigar lover ... no. once you put coins on the scale, that counts as a weighing, and every time you remove coins it counts as a weighing. this boils down to the 3-3-2 solution above. the first time you remove 2 and weight, you are weighing 3-3. at that point there are 3 possibilities still. the scale is even, or one or the other side is down. you have to do one more weighing from there.

If we write return statement in try, catch and finally block, which one will execute when and why ?

4 Answers

Iterative method to find the height of a tree

2 Answers

why compilers are not compatible in every processor?

2 Answers

finding an element in rotated sorted array.

2 Answers

Can you take complete ownership of the work you do?

2 Answers

Find Loop in a Binary Tree.

2 Answers

There are 3 baskets basket A contains apples, basket B contains oranges and basket C contains a mixture of both. All there baskets are wrongly labelled. Now from the 3 baskets pick one fruit such that you can rename the baskets correctly.

2 Answers

Questions were mostly based on OOPS JAVA, String manipulations, Data-Structures, Puzzles

2 Answers

Lots of questions on trees, arrays and sorting.

3 Answers

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