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given 8 coins and one of them heavier than the others, how many weighings will be needed to find the odd one ?

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two weighings are needed. separate into three groups (3,3,2) put three on each side of scale, if sides balance then place two remaining coins on either side of scale to see which is heavier. If sides don't balance, take two coins from the heavier side and put on the scale to see if one is heavier, if they balance, the one you took off is the heaviest.

One weighing. Place four coins in each pan. Take two off at a time until the scale balances. The heavier coin will be in the hand of the pan that ascends.

@Cigar lover ... no. once you put coins on the scale, that counts as a weighing, and every time you remove coins it counts as a weighing. this boils down to the 3-3-2 solution above. the first time you remove 2 and weight, you are weighing 3-3. at that point there are 3 possibilities still. the scale is even, or one or the other side is down. you have to do one more weighing from there.

Iterative method to find the height of a tree

2 Answers

why compilers are not compatible in every processor?

2 Answers

finding an element in rotated sorted array.

2 Answers

Lots of questions on trees, arrays and sorting.

2 Answers

There was a number, say it is present on a number plate or some thing, when it is roteted by 180 degree it gives another number. Subtracting the 2nd from the 1st gives us another number which was provided to me. I don't remember the exact number. Find the initial number.

2 Answers

If we write return statement in try, catch and finally block, which one will execute when and why ?

4 Answers

Nothing unexpected

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cut a cake in 8 equal parts , you can use at most 3 cuts

2 Answers

I had never used qsort in C. The interviewer had to tell me the syntax.

1 Answer
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