Senior java developer Interview Questions

You can use & modify below query - select e.ename, dep.loc from emp e, (select d.deptno, d.dname, d.loc from dept d, (select deptno dno, count(*) ct from emp group by deptno order by deptno desc) dn where rownum = 1 and dn.dno = d.deptno) dep where e.deptno = dep.deptno order by e.ename;

I think query will be like given below. Check or change a bit for your requirements. select EMP.ENAME, lc.LOCNAME from employee emp, company org, location lc where emp.cID = ORG.CID and org.locID = lc.locID and lc.locID in ( select place.locID from ( select loc.locID, count(*) ct from employee e, company c, location loc where e.cID = c.cID and c.locID = loc.locID group by loc.locID order by ct desc) place where rownum = 1); Enjoy :)

These people in ADP have been in such a comfort zone that they don't like to pick more capable people who can challenge their capability disturbing their comfort zone & rest who cares about the profits of the company till the time salary is getting credited in the account with less or no work. So continue to show-off & keep capable people away.

let string:String = "AAAAABBBVVVCVCAA" let characters = Array(string) var counter:Int = 1 var newArray:[String] = [String]() let lastCount = characters.count - 1 for count in 0...(characters.count - 2) { if characters[count] == characters[count + 1] { counter = counter + 1; }else { newArray.append("\(counter)\(characters[count])") counter = 1 } if lastCount == count + 1 { newArray.append("\(counter)\(characters[count])") } } print(newArray)

public static void main(String[] args) { String s = "AAAAAAAAAAAAAAAAAABBBBBBBBBBBBBBCC"; Set set = new HashSet(); char b = 0; int count = 1; String newString = ""; for (int i = 0; i 0) { b = s.charAt(i - 1); } char c = s.charAt(i); if (!set.add(c)) { count++; } else { if (b != 0) { newString = newString + b + count; count = 1; } } } newString = newString + b + count; System.out.println(newString); }

public static void main(String[] args) { String s = "AAAAAAAAAAAAAAAAAABBBBBBBBBBBBBBCC"; Set set = new HashSet(); char b = 0; int count = 1; String newString = ""; for (int i = 0; i 0) { b = s.charAt(i - 1); } char c = s.charAt(i); if (!set.add(c)) { count++; } else { if (b != 0) { newString = newString + b + count; count = 1; } } } newString = newString + b + count; System.out.println(newString); }

Convert BST to DLL (sorted), and find the pair in linear time.

The key in these questions is to cover the fundamentals, and be ready for the back-and-forth with the interviewer. Might be worth doing a mock interview with one of the MobiKwik or ex-MobiKwik Senior Java Developer experts on Prepfully? They give real-world practice and guidance, which is pretty helpful. prepfully.com/practice-interviews

I said due to salary & work there. To this HCL manager says that I am a selfish person & because of my kind of people India is not getting good work. What a rubbish statement from a Manager.

Don't believe any positive negative reviews, just apply your logic, these HCL like companies hire cheap, third class managers to exploit other employees. And these companies manipulate the reviews on Glassdoor also.

Difference between array list and linked list,

Depends on many factors , implementing better hash code and loadfactor.

spring, hibernate, rest jsp and servlet and threading. prepare each module of spring in detail. Thread synchronization and all the possible scenario on the same, all the basic keywords of java, string programs, for loop programs and what not basically u need to be good at everything to clear deloitte

Inner class- it is used for nested class, it can have all the access of outer class and can have access to private method as well. It can have any type of modifier defined.

what kind of program they ask?

plz tell me what kinf of program they ask?