Arity
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Arity interview question
Code Fibonacci sequence
Interview Answer
Anonymous
15 Nov 2018
In R: fibon.Seq<- function(n){ recurring.Mat <- matrix(c(0,1),nrow=1) A <- matrix(c(0,1,1,1),nrow = 2) for(i in 1:n){ recurring.Mat <- recurring.Mat%*%A } return(recurring.Mat[2]) }