How would you find the square root of 1.2?
Anonymous
Figured it could be approximated by considering that the square root of 121 is 11, so the answer must be close to 10.9 scaled down to 1.09. (Although I got this wrong at first by scaling down too far to 0.109 and had to be corrected.) This was followed by many questions asking how I could obtain the result using an FPGA which allowed me to talk about CORDIC, and other methods of approximations that I tried to dream up - most were probably incorrect but I think they may have liked how hard I tried to come up with alternate ideas.
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