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The interview focused on evaluating my approach to technical problem solving, security tradeoff reasoning, how I collaborate across teams when handling vulnerability work, and how I prioritize reliability / availability / confidentiality considerations.
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Senior DevSecOps

Interviewed at Pleo

3.2★
10 Nov 2025

The interview focused on evaluating my approach to technical problem solving, security tradeoff reasoning, how I collaborate across teams when handling vulnerability work, and how I prioritize reliability / availability / confidentiality considerations.

You have a hierarchy of directories and some files in some of those directories: /root/devops/dir1/file1.txt, file2.txt, ... /root/devops/dir2/file3.txt, file4, ... /root/devops/file6.in, file7.out, ... ... Some of these files contain IP addresses inside the text. An IP address is a string of form x.x.x.x where each x is a number from 0 to 255 (inclusive). For example, say we have file1.txt that looks like this: hello world 127.0.0.1 this is some example 128.99.107.55 file with some correct and incorrect 128.128.4.11 ip 0.11.1115.78 addresses This file contains only 3 IP addresses, namely 127.0.0.1, 128.99.107.55, and 128.128.4.11, since 0.11.1115.78 is not a valid IP address. Your task is to find all distinct IP addresses from all the files in the /root/devops/ directory and print them in lexicographical order. Example For the following /root/devops/ directory: /root/devops/dir1/file1.txt hello world 127.0.0.1 this is some example 128.99.107.55 file with some correct and incorrect 128.128.4.11 ip 0.11.1115.78 addressesaddresses /root/devops/dir1/file2.txt hello from 74.0.65.76 and 8.dd.99.88.907 good this is some example 306.5.76.35 file with some correct and incorrect 15.128.4.65 ip addresses 0.0.0.0 /root/devops/dir2/file3.txt 127.65.64.1 127.0.64.1 127.0.0.1 exaMple 128.57.107.76 128.57.907.70 file with some correct and incorrect 67.128.4.11 ip addresses 7.7.7.8 /root/devops/dir2/file4.txt hello world 127.98.0.1 this is some example 128.96.107.55 file with some correct and incorrect 128.68.4.11 ip addresses /root/devops/f.inp hello world 127.0.49.1 this is some example 128.99.58.55 8.88.888.88 77.255.255.254 7.7.257.25 file with some correct and incorrect 26.56.4.23 ip addresses the output should be 0.0.0.0 127.0.0.1 127.0.49.1 127.0.64.1 127.65.64.1 127.98.0.1 128.128.4.11 128.57.107.76 128.68.4.11 128.96.107.55 128.99.107.55 128.99.58.55 15.128.4.65 26.56.4.23 67.128.4.11 7.7.7.8 74.0.65.76 77.255.255.254 [execution time limit]
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Senior DevSecOps Engineer

Interviewed at Visa Inc.

3.8★
5 Nov 2025

You have a hierarchy of directories and some files in some of those directories: /root/devops/dir1/file1.txt, file2.txt, ... /root/devops/dir2/file3.txt, file4, ... /root/devops/file6.in, file7.out, ... ... Some of these files contain IP addresses inside the text. An IP address is a string of form x.x.x.x where each x is a number from 0 to 255 (inclusive). For example, say we have file1.txt that looks like this: hello world 127.0.0.1 this is some example 128.99.107.55 file with some correct and incorrect 128.128.4.11 ip 0.11.1115.78 addresses This file contains only 3 IP addresses, namely 127.0.0.1, 128.99.107.55, and 128.128.4.11, since 0.11.1115.78 is not a valid IP address. Your task is to find all distinct IP addresses from all the files in the /root/devops/ directory and print them in lexicographical order. Example For the following /root/devops/ directory: /root/devops/dir1/file1.txt hello world 127.0.0.1 this is some example 128.99.107.55 file with some correct and incorrect 128.128.4.11 ip 0.11.1115.78 addressesaddresses /root/devops/dir1/file2.txt hello from 74.0.65.76 and 8.dd.99.88.907 good this is some example 306.5.76.35 file with some correct and incorrect 15.128.4.65 ip addresses 0.0.0.0 /root/devops/dir2/file3.txt 127.65.64.1 127.0.64.1 127.0.0.1 exaMple 128.57.107.76 128.57.907.70 file with some correct and incorrect 67.128.4.11 ip addresses 7.7.7.8 /root/devops/dir2/file4.txt hello world 127.98.0.1 this is some example 128.96.107.55 file with some correct and incorrect 128.68.4.11 ip addresses /root/devops/f.inp hello world 127.0.49.1 this is some example 128.99.58.55 8.88.888.88 77.255.255.254 7.7.257.25 file with some correct and incorrect 26.56.4.23 ip addresses the output should be 0.0.0.0 127.0.0.1 127.0.49.1 127.0.64.1 127.65.64.1 127.98.0.1 128.128.4.11 128.57.107.76 128.68.4.11 128.96.107.55 128.99.107.55 128.99.58.55 15.128.4.65 26.56.4.23 67.128.4.11 7.7.7.8 74.0.65.76 77.255.255.254 [execution time limit]

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