Analyst Interview Questions | Glassdoor.co.in

# Analyst Interview Questions

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Analyst interview questions shared by candidates

## Top Interview Questions

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30 May 2012
 How many smaller cubes are completely invisible in a n*n*n rubic's cube?7 Answersn^3- 6n^2 The number of cubes are n^3(volume). The number of cubes exposing one or more sides( 6 *( n^2) - all cubes on the sides.) Number of invisible cubes are n^3- 6n^2 .Isn't the answer none since the question says "completely invisible"? every unit is visible by at least one side so any sub cube (made of these units) has a portion exposed.N*N*N-(N*N*2+N*(N-2)*2+(N-2)*(N-2)*2)Show more responses(N-2)^3(n-2)^3 you can verify by assuming n=4. Try to visualize invisible cubes and compare it with answers.(n-2)^3 you can verify by assuming n=4. Try to visualize invisible cubes and compare it with answers.(n-2)*(n-2)*(n-2)

21 Nov 2012

### Programmer Analyst at Atos-Syntel was asked...

9 Dec 2012
 Use 10 trees and plant them in 4 rows such that each row has atleast 4 trees7 Answerstry diagonal star shapetry diagonalby put it in " s "shapeShow more responsestry a triangletriangle shpe . . . . . . . . .triangle - - - - - - - - -. . . . . . . . . .

19 Aug 2012
 How'll you find the weight of an object attached to another object without detaching them and without using any weighing machines. Both the weights are unknown8 AnswersIf the objects are linked by a thread, I'd just put each object one side of my arm and let the heavier one go down while the lighter one goes upTheMigthyBat, no they're attached as in bolted together. You don't know the weight of either of them. And it's not about finding the heavier of them, it's about finding the exact weight of one of them without disturbing them.Cant we just see the amount of water displaced by the object and then calculate the weight? I think its easy that way, as we can control the volume immersed in water. (let it be attached in any way)Show more responsesI think we can take a perfect model of both objects and weigh them separately...by immersing them in a liquid....one by one....and checking the amount of volume displaced.......and applying principles on the liquid collectedimmersing in the liquiud is the ans to thi s ques ... bt still then they are connected together so the total volume obtained would the sum of both objects .. then how could we find the volume of each one ..Water displacement theory seems to be nice. Since there is no information regarding how they are attached we can do the following way. catch one weighted and dip the other weight in water. Some water will be displaced. Now repaeat the same in revesrese order. i.e catch the second side and dip the other weight. Now calculate the amount of water displaced in both the cases. greater displacement - lesser water displacement. Now immerse completely both the objects and find the displacement of water. by this you can arrive at the answerits simply and easy. Let us use the simple way to determine which is heavier. Let us assume the weights are connected with the thread. And use the water displacement. And we can use the six standard mathematics (A+b) whole square formulae. We can calculate the weight of the object

### Research Analyst at WorldQuant was asked...

14 Mar 2011
 You are given 2 eggs. * You have access to a 100-storey building. * Eggs can be very hard or very fragile means it may break if dropped from the first floor or may not even break if dropped from 100 th floor.Both eggs are identical. * You need to figure out the highest floor of a 100-storey building an egg can be dropped without breaking. * Now the question is how many drops you need to make. You are allowed to break 2 eggs in the process7 Answersfloor(n/2) + 2(n-1+floor(99/n)) is minimal for n=10. You drop the egg from the 10th floor, if it breaks, than you go one-by-one from the first floor -> 10 trials. If it does not break, you drop it from the 20th floor. If it breaks, you go from 11 to 19 -> total 11 trials. Worst case: you drop it from 10, 20, 30, 40, 50, 60, 70, 80, 90 (break), 81,82,83,84,85,86,87,88,89 -> 18 trials. (If it does not break on 90, you can go for 95, and have tha answer in 14 drops worst case). So tha answer is 18.floor(n/2) + 1Show more responsesfirst egg, try floors at 14, 27, 39, 50, 60, 69, 77, 84, 90, 95, 99, 100 second egg then try floors in between, then no more than 14 tries total in worst casefor n floor building answer will be Int refers to rounding of the closest integer. Int(sqrt(n))) - 1*Z + (IntSqrt(n) - 1) + (n - M) where Z = 0 if n - Int(sqrt(n))^2 > 0 Z = 1 if n - Int(sqrt(n))^2 <= 0 and M is maximum integer multiple of Int(sqrt(n) <= n50 times: 2,4,6,...,100earlier answer 14 drops is wrong because if the floor at which egg breaks is 68, it will require 15 drops: 14 27 39 40 50 60 69 61 62 63 64 65 66 67 68 Therefore the minimum drops is 15: drop first egg in these floors. no chance you will need to drop more that 15 times. 15 29 42 54 55 65 74 82 89 95 100

### Financial Analyst - Mortgage at XL Dynamics was asked...

17 Dec 2010
 Tell me about the role of mortgage analyst or how they work.6 AnswersHow can one answer without having exp. in that field You can say whatever they have mentioned in the work profileYOUR EXPERIENCE IS REALLY GOOD........& ITS GOOD THAT U HAV NARATTED HERE,......ITS REALLY HELPFUL................,can i get ur ur email id?u can mail me at hitblue22@rediffmail.comShow more responseshey can u mail me some more details... i found it good that u shared in and around details....it would help me alot as a fresher... i want to know ur personal experience and clear data about the company... thanks sourabha.sheshagiri@gmail.comhi hitblue, I really thank u for giving a clear idea. and let me mail u for detail information.Im gng interview in xl dynamics tmrw can i hv openings in Bangalore
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